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The density of a solution prepared by dissolving 120 g of urea

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Solving time: 3 mins

The density of a solution prepared by dissolving 120 g of urea (mol. mass $= 60 u$ ) in $1000 g$ of water is $1.15 g / mL$ . The molarity of this solution is

0.50 M

1.78 M

1.02 M

2.05 M

Views: 5,987 students

Updated on: Aug 20, 2023

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2012

Found 2 tutors discussing this question

James Discussed

The density of a solution prepared by dissolving 120 g of urea (mol. mass

= 60 u

) in

1000 g

of water is

1.15 g / mL

. The molarity of this solution is

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

Total mass of solution

= 1000 g

water

+ 120 g

urea

= 1120 g

Density of solution

= 1.15 g / mL

Thus, volume of solution

= \frac{mass}{density} = \frac{1120 g}{1.15 g / mL}

= 973.91 mL = 0.974 L

Moles of solute

= \frac{120}{60} = 2 mol

Molarity

= \frac{moles of solute}{volume ( L ) of solution} = \frac{2 mol}{0.974 L}

= 2.05 mol L^{- 1}

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Question Text	The density of a solution prepared by dissolving 120 g of urea (mol. mass $= 60 u$ ) in $1000 g$ of water is $1.15 g / mL$ . The molarity of this solution is
Updated On	Aug 20, 2023
Topic	Some Basic Concepts of Chemistry
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 15
Upvotes	1647
Avg. Video Duration	8 min

The density of a solution prepared by dissolving 120 g of urea (mol. mass $= 60 u$ ) in $1000 g$ of water is $1.15 g / mL$ . The molarity of this solution is

Text solutionVerified

Filo tutor solutions (15)

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The density of a solution prepared by dissolving 120 g of urea (mol. mass =60u ) in 1000 g of water is 1.15 g/mL. The molarity of this solution is

Text solutionVerified

Filo tutor solutions (15)

Questions from JEE Mains 2012 - PYQs

Practice questions from Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

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The density of a solution prepared by dissolving 120 g of urea (mol. mass $= 60 u$ ) in $1000 g$ of water is $1.15 g / mL$ . The molarity of this solution is