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Coordination Compounds

Valence Bond Theory

The coordination number and the oxidation state of the element

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The coordination number and the oxidation state of the element ‘E’ in the complex $[E (e n)_{2} (C_{2} O_{4})] N O_{2}$ (where (en) is ethylene diamine) are, respectively:

Name: Video solution 1: The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylene diamine) are, respectively:
Uploaded: 2022-04-26T10:54:05.000Z
Duration: 1 min
Description: Video solution 1: The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylene diamine) are, respectively:

6 and 3

6 and 2

4 and 2

4 and 3

Views: 6,261 students

Updated on: Apr 26, 2022

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Alexander Discussed

The coordination number and the oxidation state of the element ‘E’ in the complex

[E (e n)_{2} (C_{2} O_{4})] N O_{2}

(where (en) is ethylene diamine) are, respectively:

14 mins ago

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14 mins ago

Text solutionVerified

[E (en)_{2} C_{2} O_{4}] NO_{2}

∴

Coordination number of

E = 6

as en and oxalate are both bidentate ligands.
Let the oxidation number of E be x.

∴

Oxidation number of

x + 2 (0) + 1 (- 2) = + 1

x = + 3

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Question Text	The coordination number and the oxidation state of the element ‘E’ in the complex $[E (e n)_{2} (C_{2} O_{4})] N O_{2}$ (where (en) is ethylene diamine) are, respectively:
Updated On	Apr 26, 2022
Topic	Coordination Compounds
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 1
Upvotes	161
Avg. Video Duration	1 min

The coordination number and the oxidation state of the element ‘E’ in the complex $[E (e n)_{2} (C_{2} O_{4})] N O_{2}$ (where (en) is ethylene diamine) are, respectively:

Text solutionVerified

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The coordination number and the oxidation state of the element ‘E’ in the complex $[E (e n)_{2} (C_{2} O_{4})] N O_{2}$ (where (en) is ethylene diamine) are, respectively: