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Solubility product of silver bromide is {5.0}{10}^{{-{13}}}. T

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Solubility product of silver bromide is $5.0 \times 10^{- 13}$ . The quantity of potassium bromide (molar mass taken as 120 g of $mol^{- 1}$ ) to be added to 1 litre of 0.05 M solution of silver nitrate of start the precipitation of AgBr is

Name: Video solution 1: Solubility product of silver bromide is 5.0×10−13. The quantity of potassium bromide (molar mass taken as 120 g of mol−1) to be added to 1 litre of 0.05 M solution of silver nitrate of start the precipitation of AgBr is
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: Solubility product of silver bromide is 5.0×10−13. The quantity of potassium bromide (molar mass taken as 120 g of mol−1) to be added to 1 litre of 0.05 M solution of silver nitrate of start the precipitation of AgBr is

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Solubility product of silver bromide is

5.0 \times 10^{- 13}

. The quantity of potassium bromide (molar mass taken as 120 g of

mol^{- 1}

) to be added to 1 litre of 0.05 M solution of silver nitrate of start the precipitation of AgBr is

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Question Text	Solubility product of silver bromide is $5.0 \times 10^{- 13}$ . The quantity of potassium bromide (molar mass taken as 120 g of $mol^{- 1}$ ) to be added to 1 litre of 0.05 M solution of silver nitrate of start the precipitation of AgBr is
Answer Type	Video solution: 1
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Solubility product of silver bromide is 5.0×10−13. The quantity of potassium bromide (molar mass taken as 120 g of mol−1) to be added to 1 litre of 0.05 M solution of silver nitrate of start the precipitation of AgBr is

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Solubility product of silver bromide is $5.0 \times 10^{- 13}$ . The quantity of potassium bromide (molar mass taken as 120 g of $mol^{- 1}$ ) to be added to 1 litre of 0.05 M solution of silver nitrate of start the precipitation of AgBr is