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Given: {{E}_{{{F}{e}^{{{3}+}}/{F}{e}}}^{{}}}=-{0.036}{V},{{E}_

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Given: $E_{F e^{3 +} / F e}^{\circ} = - 0.036 V, E_{F e^{2 +} / F e}^{\circ} = - 0.439 V$ . The value of standard electrode potential for the change, $F e_{(a q)}^{3 +} + e^{-} \to F e^{2 +}$ (aq) will be :

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Given:

E_{F e^{3 +} / F e}^{\circ} = - 0.036 V, E_{F e^{2 +} / F e}^{\circ} = - 0.439 V

. The value of standard electrode potential for the change,

F e_{(a q)}^{3 +} + e^{-} \to F e^{2 +}

(aq) will be :

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Question Text	Given: $E_{F e^{3 +} / F e}^{\circ} = - 0.036 V, E_{F e^{2 +} / F e}^{\circ} = - 0.439 V$ . The value of standard electrode potential for the change, $F e_{(a q)}^{3 +} + e^{-} \to F e^{2 +}$ (aq) will be :
Answer Type	Video solution: 1
Upvotes	150