Given ECr3+/Cr∘=−0.72V,EFe2+/Fe∘=−0.42V. The potential for the cell Cr/Cr3+(0.1)∣∣∣∣Fe2+(0.01M)∣∣∣∣Fe is

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Given {{E}_{{{C}{r}^{{{3}+}}/{C}{r}}}^{{}}}=-{0.72}{V},{{E}_{{

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Given $E_{C r^{3 +} / C r}^{\circ} = - 0.72 V, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V$ . The potential for the cell $C r / C r^{3 +} (0.1) ∣ ∣ ∣ ∣ F e^{2 +} (0.01 M) ∣ ∣ ∣ ∣ F e$ is

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Benjamin Discussed

Given

E_{C r^{3 +} / C r}^{\circ} = - 0.72 V, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V

. The potential for the cell

C r / C r^{3 +} (0.1) ∣ ∣ ∣ ∣ F e^{2 +} (0.01 M) ∣ ∣ ∣ ∣ F e

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Question Text	Given $E_{C r^{3 +} / C r}^{\circ} = - 0.72 V, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V$ . The potential for the cell $C r / C r^{3 +} (0.1) ∣ ∣ ∣ ∣ F e^{2 +} (0.01 M) ∣ ∣ ∣ ∣ F e$ is
Answer Type	Video solution: 1
Upvotes	150