For the following reaction, equilibrium constant Kc at 298 K is 1.6×1017 Fe(aq)2++S(aq)2⇔FeS(s) When equal volume of 0.06 MFe2+ and 0.2 Ms−2 solution are mixed, then equilibrium concentration of Fe2+ is found to be Y×10−17M. Y is

Click here to view the solution.

Get 2 FREE Instant-Explanations on Filo with code FILOAPP

For the following reaction, equilibrium constant {K}_{{{c}}} a

Question

For the following reaction, equilibrium constant $K_{c}$ at 298 K is $1.6 \times 10^{17}$
$F e_{(a q)}^{2 +} + S_{(a q)}^{2} \Leftrightarrow F e S (s)$
When equal volume of 0.06 $M F e^{2 +}$ and 0.2 $M s^{- 2}$ solution are mixed, then equilibrium concentration of $F e^{2 +}$ is found to be $Y \times 10^{- 17} M$ . Y is

Views: 984 students

Found 5 tutors discussing this question

Noah Discussed

For the following reaction, equilibrium constant

K_{c}

at 298 K is

1.6 \times 10^{17}

F e_{(a q)}^{2 +} + S_{(a q)}^{2} \Leftrightarrow F e S (s)

When equal volume of 0.06

M F e^{2 +}

and 0.2

M s^{- 2}

solution are mixed, then equilibrium concentration of

F e^{2 +}

is found to be

Y \times 10^{- 17} M

. Y is

7 mins ago

Discuss this question LIVE

7 mins ago

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our all tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text