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Uniform Circular Motion

For a particle in uniform circular motion, the acceleration {a

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Solving time: 2 mins

For a particle in uniform circular motion, the acceleration $a$ at a point $P (R, θ)$ on the circle of radius $R$ is (Here $θ$ is measured from the $x$ -axis)

- \frac{v ^{2}}{R} cos θ \hat{i} + \frac{v ^{2}}{R} sin θ \hat{j}

- \frac{v ^{2}}{R} sin θ \hat{i} + \frac{v ^{2}}{R} cos θ \hat{j}

- \frac{v ^{2}}{R} cos θ \hat{i} - \frac{v ^{2}}{R} sin θ \hat{j}

\frac{v ^{2}}{R} \hat{i} + \frac{v ^{2}}{R} \hat{j}

Views: 6,713 students

Updated on: Aug 2, 2023

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Mateo Discussed

For a particle in uniform circular motion, the acceleration

a

at a point

P (R, θ)

on the circle of radius

R

is (Here

θ

is measured from the

x

-axis)

7 mins ago

Discuss this question LIVE

7 mins ago

Text solutionVerified

Let us draw the diagram at first
Solution Image

Acceleration is given by

a = a_{c} cos θ (- \hat{i}) + a_{c} sin θ (- \hat{j})

But we know that

a = \frac{v ^{2}}{R}

So, we can write the above expression as

a = \frac{- v ^{2}}{R} cos θ \hat{i} - \frac{v ^{2}}{R} sin θ \hat{j}

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Question Text	For a particle in uniform circular motion, the acceleration $a$ at a point $P (R, θ)$ on the circle of radius $R$ is (Here $θ$ is measured from the $x$ -axis)
Updated On	Aug 2, 2023
Topic	Motion in a Plane
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 7
Upvotes	620
Avg. Video Duration	8 min

For a particle in uniform circular motion, the acceleration $a$ at a point $P (R, θ)$ on the circle of radius $R$ is (Here $θ$ is measured from the $x$ -axis)

Text solutionVerified

Filo tutor solutions (7)

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