For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm pressure is 2∘C. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure ( mm of Hg ) of the solution is (take Kb=0.76 K kg mol−1 ).

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Elevation in boiling point

For a dilute solution containing 2.5 {~g} of a non-volatile no

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For a dilute solution containing $2.5 g$ of a non-volatile non-electrolyte solute in $100 g$ of water, the elevation in boiling point at $1 atm$ pressure is $2^{\circ} C$ . Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure ( $mm$ of $Hg$ ) of the solution is (take $K_{b} = 0.76 K kg mol^{- 1}$ ).

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For a dilute solution containing

2.5 g

of a non-volatile non-electrolyte solute in

100 g

of water, the elevation in boiling point at

1 atm

pressure is

2^{\circ} C

. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (

mm

Hg

) of the solution is (take

K_{b} = 0.76 K kg mol^{- 1}

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Question Text	For a dilute solution containing $2.5 g$ of a non-volatile non-electrolyte solute in $100 g$ of water, the elevation in boiling point at $1 atm$ pressure is $2^{\circ} C$ . Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure ( $mm$ of $Hg$ ) of the solution is (take $K_{b} = 0.76 K kg mol^{- 1}$ ).
Updated On	May 22, 2023
Topic	Solutions
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 3
Upvotes	310
Avg. Video Duration	8 min

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