Equation of three lines $\vec{r}=\lambda \hat{i},\vec{r}=\mu \left(\hat{i}+\hat{j}\right),\vec{r}=\gamma \left(\hat{i}+\hat{j}+\hat{k}\right)$ and a plane $x+y+z=1$ are given
then area of triangle formed by point of intersectioin of line and plane is $\Delta$then ${\left(6\Delta \right)}^2$equals

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