Question
During Searle’s experiment, zero of the Vernier scale lies between and of the main scale. The division of the Vernier scale exactly coincids with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between m and m of the main scale but now the division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is . The least count of the Vernier scale is . The maxiumn perectage error in the Youngs's modulus of the wire is .
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Question Text | During Searle’s experiment, zero of the Vernier scale lies between and of the main scale. The division of the Vernier scale exactly coincids with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between m and m of the main scale but now the division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is . The least count of the Vernier scale is . The maxiumn perectage error in the Youngs's modulus of the wire is . |