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Dissolving 120 g of urea (mol.wt.60) in 1000 g of water gave a

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Dissolving 120 g of urea (mol.wt.60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is:

1.78 M

2.00 M

2.05 M

2.22 M

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Updated on: Sep 2, 2023

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Dissolving 120 g of urea (mol.wt.60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is:

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Text solutionVerified

Mass of solute

= 120 g

Mass of water

= 1000 g

Mass of solution

= 1120 g

∴

Volume of solution

(\frac{m}{d}) = \frac{1120}{1.15} mL

Milli mole

= M \times V_{in mL}

\frac{120}{60} \times 1000 = M \times \frac{1120}{1.15}

∴ M = 2.05

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Question Text	Dissolving 120 g of urea (mol.wt.60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is:
Updated On	Sep 2, 2023
Topic	Some Basic Concepts of Chemistry
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 14
Upvotes	1351
Avg. Video Duration	5 min

Dissolving 120 g of urea (mol.wt.60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is:

Text solutionVerified

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Dissolving 120 g of urea (mol.wt.60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is:

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