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Some Basic Concepts of Chemistry

Stoichiometry and Stoichiometric calculations

At 300 {~K} and 1 {~atm}, 15 {~mL} of a gaseous hydrocarbon re

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Medium

Solving time: 3 mins

At $300 K$ and $1 atm, 15 mL$ of a gaseous hydrocarbon requires $375 mL$ air containing 20 % $O_{2}$ by volume for complete combustion. After combustion, the gases occupy $330 mL$ . Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is
(a) $C_{3} H_{8}$
(b) $C_{4} H_{8}$
(c) $C_{3} H_{6}$
(d) None

Views: 6,085 students

Updated on: Dec 6, 2023

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2016

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300 K

and

1 atm, 15 mL

of a gaseous hydrocarbon requires

375 mL

air containing 20 %

O_{2}

by volume for complete combustion. After combustion, the gases occupy

330 mL

. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is
(a)

C_{3} H_{8}

(b)

C_{4} H_{8}

(c)

C_{3} H_{6}

(d) None

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Question Text	At $300 K$ and $1 atm, 15 mL$ of a gaseous hydrocarbon requires $375 mL$ air containing 20 % $O_{2}$ by volume for complete combustion. After combustion, the gases occupy $330 mL$ . Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is (a) $C_{3} H_{8}$ (b) $C_{4} H_{8}$ (c) $C_{3} H_{6}$ (d) None
Updated On	Dec 6, 2023
Topic	Some Basic Concepts of Chemistry
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 31
Upvotes	3118
Avg. Video Duration	9 min

Text solutionVerified

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