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Assuming 2 s-2 p mixing is not operative, the paramagnetic spe

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Assuming $2 s - 2 p$ mixing is not operative, the paramagnetic species among the following is :

B e_{2}

B_{2}

C_{2}

N_{2}

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Updated on: Aug 5, 2023

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Assuming

2 s - 2 p

mixing is not operative, the paramagnetic species among the following is :

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Text solutionVerified

Assuming that no

2 s - 2 p

mixing takes place, then molecular orbitals may be arranged in order of energy as follows:

σ_{1 s}, σ_{1 s}^{*}, σ_{2 s}, σ_{2 s}^{*}, σ_{2 p_{z}}, π_{2 p_{x}} = π_{2 p_{y}}, π_{2 p_{x}}^{*} = π_{2 p_{y}}^{*}, σ_{2 p_{z}}

Applying this configuration,
(A)

B e_{2} : σ_{1 s}^{2}, σ_{1 s}^{* 2}, σ_{2 s}^{2}, σ_{2 s}^{* 2}

(B)

B_{2} : σ_{1 s}^{2}, σ_{1 s}^{* 2}, σ_{2 s}^{2}, σ_{2 s}^{* 2}, π_{2 p_{x}}^{1} = π_{2 p_{y}}^{1}

(C)

C_{2} : σ_{1 s}^{2}, σ_{1 s}^{* 2}, σ_{2 s}^{2}, σ_{2 s}^{* 2}, π_{2 p_{x}}^{2} = π_{2 p_{y}}^{2}

(D)

N_{2} : σ_{1 s}^{2}, σ_{1 s}^{* 2}, σ_{2 s}^{2}, σ_{2 s}^{* 2}, π_{2 p_{x}}^{2} = π_{2 p_{y}}^{2}, σ_{2 p_{z}}^{2}

We know that when electrons in the molecular orbitals are unpaired, they are paramagnetic in nature, while when paired, they are diamagnetic in nature.
From the electronic configurations, we see that

B e_{2}, C_{2}

and

N_{2}

will be diamagnetic, but

B_{2}

will be paramagnetic.

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Question Text	Assuming $2 s - 2 p$ mixing is not operative, the paramagnetic species among the following is :
Updated On	Aug 5, 2023
Topic	Chemical Bonding and Molecular Structure
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 9
Upvotes	1072
Avg. Video Duration	6 min

Assuming $2 s - 2 p$ mixing is not operative, the paramagnetic species among the following is :

Text solutionVerified

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Assuming 2s−2p mixing is not operative, the paramagnetic species among the following is :

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Assuming $2 s - 2 p$ mixing is not operative, the paramagnetic species among the following is :