Arrange the carbanions, (CH3)3C,CCl3,(CH3)2CH,C6H5 CH2 in order of their decreasing stability:

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Organic Chemistry-Some Basic Principles and Techniques

Factors affecting reactivity

Arrange the carbanions, ({CH}_{3})_{3} {{C}}, {{C}} {Cl}_{3},(

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Arrange the carbanions, $(CH_{3})_{3} \overline{C}, \overline{C} Cl_{3}, (CH_{3})_{2} \overline{C} H, C_{6} H_{5}$ $\overline{C} H_{2}$ in order of their decreasing stability:

C_{6} H_{5} \overline{C} H_{2} > \overline{C} Cl_{3} > (CH_{3})_{3} \overline{C} > (CH_{3})_{2} < \overline{C} H

(CH_{3})_{2} \overline{C} H > \overline{C} Cl_{3} > C_{6} H_{5} \overline{C} H_{2} > (CH_{3})_{3} \overline{C}

\overline{C} Cl_{3} > C_{6} H_{5} \overline{C} H_{2} > (\overline{C} H_{3})_{2} CH > (\overline{C} H_{3})_{3} C

(CH_{3})_{3} \overline{C} > (CH_{3})_{2} \overline{C} H > C_{6} H_{5} \overline{C} H_{2} > \overline{C} Cl_{3}

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Updated on: Mar 21, 2023

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Alexander Discussed

Arrange the carbanions,

(CH_{3})_{3} \overline{C}, \overline{C} Cl_{3}, (CH_{3})_{2} \overline{C} H, C_{6} H_{5}

\overline{C} H_{2}

in order of their decreasing stability:

9 mins ago

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9 mins ago

Text solutionVerified

C - C l_{3}

C l^{-}

being electronegative stabilizes the carbanion, in

C_{6} H_{5} CH_{2}^{-}

, the presence of phenyl group stabilizes it due to resonance and in case of secondary and tertiary, the order of reactivity is

2^{\circ} > 3^{\circ}

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Question Text	Arrange the carbanions, $(CH_{3})_{3} \overline{C}, \overline{C} Cl_{3}, (CH_{3})_{2} \overline{C} H, C_{6} H_{5}$ $\overline{C} H_{2}$ in order of their decreasing stability:
Updated On	Mar 21, 2023
Topic	Organic Chemistry-Some Basic Principles and Techniques
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 4
Upvotes	456
Avg. Video Duration	10 min

Arrange the carbanions, $(CH_{3})_{3} \overline{C}, \overline{C} Cl_{3}, (CH_{3})_{2} \overline{C} H, C_{6} H_{5}$ $\overline{C} H_{2}$ in order of their decreasing stability:

Text solutionVerified

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Arrange the carbanions, $(CH_{3})_{3} \overline{C}, \overline{C} Cl_{3}, (CH_{3})_{2} \overline{C} H, C_{6} H_{5}$ $\overline{C} H_{2}$ in order of their decreasing stability: