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Thermodynamic process

An ideal gas is expanding such that {PT}^{2}= constant. The co

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An ideal gas is expanding such that $PT^{2} =$ constant. The coefficient of volume expansion of the gas is :

\frac{1}{T}

\frac{2}{T}

\frac{3}{T}

\frac{4}{T}

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Updated on: Mar 22, 2023

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An ideal gas is expanding such that

PT^{2} =

constant. The coefficient of volume expansion of the gas is :

5 mins ago

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Text solutionVerified

PT^{2} =

constant

(\frac{nRT}{v}) T^{2} = co n s t an t

T^{3} V^{- 1} = co n s t an t

T^{3} = kV

\Rightarrow 3 \frac{Δ T}{T} = \frac{Δ V}{V} \dots (1)

Δ V = V γ Δ T \dots (2)

comparing (1) and (2)

we get

γ = \frac{3}{T}

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Question Text	An ideal gas is expanding such that $PT^{2} =$ constant. The coefficient of volume expansion of the gas is :
Updated On	Mar 22, 2023
Topic	Thermodynamics
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 11
Upvotes	893
Avg. Video Duration	8 min

An ideal gas is expanding such that $PT^{2} =$ constant. The coefficient of volume expansion of the gas is :

Text solutionVerified

Filo tutor solutions (11)

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An ideal gas is expanding such that $PT^{2} =$ constant. The coefficient of volume expansion of the gas is :