[Solved] A small object of uniform density rolls up a curved surface with an initial velocity ′v′ . It reaches upto a maximum height of 4g3v2 with respect to the initial position. The object is : - Chemistry 9th Edition(Edition)

Using mechanical energy conservation21mv2(1+R2k2)=mg(4 g3v2)1+R2k2=23R2k2=21 So, body is disc or solid cylinder.

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A small object of uniform density rolls up a curved surface wi

Chemistry 9th Edition by Steven S. Zumdahl, Susan A. Zumdahl

Chemistry 9th Edition Edition

Author:

Steven S. Zumdahl, Susan A. Zumdahl

High School Chemistry

Chapter 1: Chapter 1

51 questions

Chapter 2: Chapter 2

27 questions

Chapter 3: Chapter 3

73 questions

Chapter 4: Chapter 4

55 questions

Chapter 5: Chapter 5

35 questions

Chapter 6: Chapter 6

34 questions

Chapter 7: Chapter 7

91 questions

Chapter 8: Chapter 8

47 questions

Chapter 9: Chapter 9

33 questions

Chapter 10: Chapter 10

42 questions

Chapter 11: Chapter 11

30 questions

Chapter 12: Chapter 12

56 questions

Chapter 13: Chapter 13

52 questions

Chapter 14: Chapter 14

74 questions

Chapter 15: Chapter 15

33 questions

Chapter 16: Chapter 16

40 questions

Chapter 17: Chapter 17

12 questions

Chapter 18: Chapter 18

46 questions

Chapter 19: Chapter 19

3 questions

Chapter 20: Chapter 20

10 questions

Chapter 21: Chapter 21

6 questions

Chapter 22: Chapter 22

12 questions

Question

Medium

Solving time: 2 mins

A small object of uniform density rolls up a curved surface with an initial velocity $^{'} v^{'}$ . It reaches upto a maximum height of $\frac{3 v ^{2}}{4 g}$ with respect to the initial position. The object is :

Ring

Solid sphere

Hollow sphere

Disc

Views: 5,791 students

Updated on: Feb 26, 2024

Book:

Chemistry

Exam:

NEET 2013

Found 3 tutors discussing this question

Amelia Discussed

A small object of uniform density rolls up a curved surface with an initial velocity

^{'} v^{'}

. It reaches upto a maximum height of

\frac{3 v ^{2}}{4 g}

with respect to the initial position. The object is :

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

Using mechanical energy conservation

\frac{1}{2} mv^{2} (1 + \frac{k ^{2}}{R ^{2}}) = mg (\frac{3 v ^{2}}{4 g}) 1 + \frac{k ^{2}}{R ^{2}} = \frac{3}{2} \frac{k ^{2}}{R ^{2}} = \frac{1}{2}

So, body is disc or solid cylinder.

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Question Text	A small object of uniform density rolls up a curved surface with an initial velocity $^{'} v^{'}$ . It reaches upto a maximum height of $\frac{3 v ^{2}}{4 g}$ with respect to the initial position. The object is :
Updated On	Feb 26, 2024
Topic	System of Particles and Rotational Motion
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 15
Upvotes	1576
Avg. Video Duration	8 min

A small object of uniform density rolls up a curved surface with an initial velocity $^{'} v^{'}$ . It reaches upto a maximum height of $\frac{3 v ^{2}}{4 g}$ with respect to the initial position. The object is :

Text solutionVerified

Filo tutor solutions (15)

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A small object of uniform density rolls up a curved surface with an initial velocity ′v′ . It reaches upto a maximum height of 4g3v2​ with respect to the initial position. The object is :

Text solutionVerified

Filo tutor solutions (15)

Questions from NEET 2013 - PYQs

Practice questions from Chemistry

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A small object of uniform density rolls up a curved surface with an initial velocity $^{'} v^{'}$ . It reaches upto a maximum height of $\frac{3 v ^{2}}{4 g}$ with respect to the initial position. The object is :