5 g of Na2SO4 was dissolved in x g of H2O . The change in freezing point was found to be 3.82∘C . If Na2SO4 is 81.5% ionised , the value of x (kf for water =1.86∘C kg mol−1) is apporximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)

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5 g of {N}{a}_{{{2}}}{S}{O}_{{{4}}} was dissolved in x g of {H

Question

5 g of $N a_{2} S O_{4}$ was dissolved in x g of $H_{2} O$ . The change in freezing point was found to be $3.82^{\circ} C$ . If $N a_{2} S O_{4}$ is $81.5 %$ ionised , the value of x
( $k_{f}$ for water = $1.86^{\circ} C$ kg $mol^{- 1}$ ) is apporximately :
(molar mass of S=32 g $mol^{- 1}$ and that of Na=23 g $mol^{- 1}$ )

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Amelia Discussed

5 g of

N a_{2} S O_{4}

was dissolved in x g of

H_{2} O

. The change in freezing point was found to be

3.82^{\circ} C

. If

N a_{2} S O_{4}

81.5 %

ionised , the value of x
(

k_{f}

for water =

1.86^{\circ} C

mol^{- 1}

) is apporximately :
(molar mass of S=32 g

mol^{- 1}

and that of Na=23 g

mol^{- 1}

)

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Question Text	5 g of $N a_{2} S O_{4}$ was dissolved in x g of $H_{2} O$ . The change in freezing point was found to be $3.82^{\circ} C$ . If $N a_{2} S O_{4}$ is $81.5 %$ ionised , the value of x ( $k_{f}$ for water = $1.86^{\circ} C$ kg $mol^{- 1}$ ) is apporximately : (molar mass of S=32 g $mol^{- 1}$ and that of Na=23 g $mol^{- 1}$ )
Answer Type	Video solution: 1
Upvotes	150